1/(x-3)+1/(x+3)=1/(x^2-9)

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Solution for 1/(x-3)+1/(x+3)=1/(x^2-9) equation:


D( x )

x-3 = 0

x^2-9 = 0

x+3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x^2-9 = 0

x^2-9 = 0

1*x^2 = 9 // : 1

x^2 = 9

x^2 = 9 // ^ 1/2

abs(x) = 3

x = 3 or x = -3

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:3) U (3:+oo)

1/(x-3)+1/(x+3) = 1/(x^2-9) // - 1/(x^2-9)

1/(x-3)+1/(x+3)-(1/(x^2-9)) = 0

1/(x-3)+1/(x+3)-(x^2-9)^-1 = 0

1/(x-3)+1/(x+3)-1/(x^2-9) = 0

(1*(x+3)*(x^2-9))/((x-3)*(x+3)*(x^2-9))+(1*(x-3)*(x^2-9))/((x-3)*(x+3)*(x^2-9))+(-1*(x-3)*(x+3))/((x-3)*(x+3)*(x^2-9)) = 0

1*(x+3)*(x^2-9)+1*(x-3)*(x^2-9)-1*(x-3)*(x+3) = 0

2*x^3-x^2-18*x+9 = 0

2*x^3-x^2-18*x+9 = 0

2*x^3-x^2-18*x+9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

x = 1

2*x^3-x^2-18*x+9 = -8

1

-1

x = -1

2*x^3-x^2-18*x+9 = 24

-1

3

x = 3

2*x^3-x^2-18*x+9 = 0

3

x-3

2*x^2+5*x-3

2*x^3-x^2-18*x+9

x-3

6*x^2-2*x^3

5*x^2-18*x+9

15*x-5*x^2

9-3*x

3*x-9

0

2*x^2+5*x-3 = 0

DELTA = 5^2-(-3*2*4)

DELTA = 49

DELTA > 0

x = (49^(1/2)-5)/(2*2) or x = (-49^(1/2)-5)/(2*2)

x = 1/2 or x = -3

x in { -3, 1/2, 3}

(x+3)*(x-1/2)*(x-3) = 0

((x+3)*(x-1/2)*(x-3))/((x-3)*(x+3)*(x^2-9)) = 0

((x+3)*(x-1/2)*(x-3))/((x-3)*(x+3)*(x^2-9)) = 0 // * (x-3)*(x+3)*(x^2-9)

(x+3)*(x-1/2)*(x-3) = 0

( x+3 )

x+3 = 0 // - 3

x = -3

( x-1/2 )

x-1/2 = 0 // + 1/2

x = 1/2

( x-3 )

x-3 = 0 // + 3

x = 3

x in { -3}

x in { 3}

x = 1/2

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